pattern A python program

Python Program

How to print patter A in python    

#code

for i in range (1,7):

    for j in range (1,7):

        if i==1 and j in {2,3,4,5}:

            print("*",end=' ')

        elif i in {2,3,4,5} and j in {1,6}:

            print("*",end=' ')

        elif i==3:

            print("*",end=' ')

        else:

            print(" ",end=' ')

    print()

#code:2

for i in range(1,6):

    for j in range(1,7):

        if i==1 and j in {2,3,4,5} or i in {2,3,4,5} and j in {1,6} or i==3:

            print("*",end='')            

        else:

            print(" ",end='')

    print()

        

explanation:

for i in range (1,7):

    for j in range (1,7):

        if i==1 and j in {2,3,4,5}:

            print("*",end=' ')

here it means after defining the range of rows an column ,

we are going to print first row of stars.

if i==1 and j in {2,3,4,5}:

using this code.

after printing first line......

elif i in {2,3,4,5} and j in {1,6}:

            print("*",end=' ')

        elif i==3:

            print("*",end=' ')

 after this we have to print the leg of A. so 

elif i in {2,3,4,5} and j in {1,6}:

            print("*",end=' ')

after it we required the middle line of A so

        elif i==3:

            print("*",end=' ')

using this code we draw the middle line of A

Afer this we have to required  

to print space such that it will appear as a right alphabet

else:

    print(" ",end='')

now to change row we required:
print()

Thankyou

    

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